Solution assignment 03 Fractional functions and graphs

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Assignment 3

Given the function:

y=-1+\displaystyle\frac{1}{x+3}

Find:
the vertical asymptote;
the horizontal asymptote;
the intersection point with the Y-as if it exists;
the intersection point with the X-as if it exists.

Based on these results sketch the result in the figure.

Solution

The vertical asymptote is x=-3. We find the horizontal asymptote when x\rightarrow\infty or x\rightarrow-\infty and that is y=-1, because the second term approaches 0 and thus y approaches -1. The intersection point with the Y-axis is y=-\displaystyle\frac{2}{3}. This result can be obtained by substituting x=0 in the function. The intersection point with the X-as is obtained by substituting y=0 and solving the following equation:

0=-1+\displaystyle\frac{1}{x+3}=\displaystyle\frac{-(x+3)}{x+3}+\displaystyle\frac{1}{x+3}=\displaystyle\frac{-x-2}{x+3}

The solution is: x=-2
See the graph in the following figure:

-1+1div(x+1)

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