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Solution assignment 03 Chain rule

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Assignment 3

Differentiate:

y=a^{2x+3}, a>0

Solution

We know the derivative:

[a^x]'=a^x\ln(a)

and thus, according to the informal method, we get:

y'=a^{2x+3}\ln(a)\cdot2=2a^{2x+3}\ln(a)

The factor 2 comes from:

(2x+3)'=2

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