Solution assignment 10 Quadratic functions and graphs

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Assignment 10

For which value of p do the parabolas:

P_1: y=x^2-4x+3
P_2: y=px^2-x+1

have just one point in common.

Solution

In the common points P_1 and P_2 the y-coordinates are equal. In order to find the corresponding x-coordinates also the right-hand sides of P_1 en P_2 have to be equal:

x^2-4x+3=px^2-x+1

(p-1)x^2+3x-2=0

This equation has only one solution (actually two coinciding solutions) if:

D=3^2-4(p-1).-2=0

Thus the two parabolas have only one common point if:

p=-\displaystyle\frac{1}{8}

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