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Solution assignment 07 Chain rule

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Assignment 7

Differentiate:

y=\sin(\sqrt{x})

Solution

Applying the informal method we get:

y'=\cos(\sqrt{x})\cdot[\sqrt{x}]'=\cos(\sqrt{x})[x^{\frac{1}{2}}]'=\displaystyle\frac{\cos(\sqrt{x})}{2\sqrt{x}}

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