Solution assignment 05 Exponential functions and graphs

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Assignment 5

Draw the graph of the function:

y=(\displaystyle\frac{1}{2})^{-x}+1

What is the formula of the asymptote?

Solution

We write:

y=(\displaystyle\frac{1}{2})^{-x}+1=(2^{-1})^{-x}+1=2^x+1

(0.5)^(-x)+1

We want to draw the graph of this function and start with the exponential function and add 1. The result is in the figure.
The asymptote of the exponential function is the X-as, i.e. y=0 and thus the de asymptote of the graph as a whole is y=1.

Return to Assignments Exponential functions and graphs

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