Solution assignment 01 Logarithmic equations

Solve:

$\ln(x+4)=2$

The equation is defined if $x+4>0$ , so if $x>-4$ (the domain).
We can write the equation as:

$\ln(x+4)=\ln(e^2)$

yielding:

$x=e^2-4$

This solution is in the domain and thus is a valid solution.