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Solution assignment 04 Exponential equations

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Assignment 4

Solve:

32-(\displaystyle\frac{1}{16})^{-3x+1}=0

Solution

We write the equation as follows:

(\displaystyle\frac{1}{16})^{-3x+1}=32

(2^{-4})^{-3x+1}=2^5

2^{12x-4}=2^5

Thus:

12x-4=5

x=\displaystyle\frac{3}{4}

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