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Solution assignment 04 Product and Quotient rule

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Assignment 4

Differentiate:

y=e^x\ln(x)

Solution

In this case we have:

f(x)=e^x

and:

g(x)=\ln(x)

and thus the product rule yields:

y'=e^x\ln(x)+e^x\displaystyle\frac{1}{x}=e^x[\ln(x)+\displaystyle\frac{1}{x}]

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