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Solution assignment 02 Product and Quotient rule

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Assignment 2

Differentiate:

(x^2+1)\ln(x)

Solution

In this function we have:

f(x)=x^2+1

and:

g(x)=\ln(x)

and thus the derivatives are:

f'(x)=2x

and:

g'(x)=\displaystyle\frac{1}{x}

The result is:

y=2x\ln(x)+(x^2+1)\displaystyle\frac{1}{x}=2x\ln(x)+x+\displaystyle\frac{1}{x}'

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