Solution assignment 14 Quadratic equations (factorizing)

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Assignment 14

Try to solve by factorizing:

$-x^2+7x-12=0$

Solution

In this equation is $a\neq1$ , but both sides can be divided by $-1$ , yielding the equation:

$x^2-7x+12=0$

We have to find $p$ and $q$ such that:

$pq=12$ and $p+q=-7$

The following values will do:

$p=-4$ and $q=-3$

Thus the equation can be written as:

$(x-4)(x-3)=0$

and thus the solutions are:

$x=4$ or $x=3$

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