Solution assignment 09 Quadratic equations (abc-formula)

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Assignment 9

For which value(s) of q does the equation:

qx^2-2x+q=0

have two coinciding solutions x.

Solution

In order to find out whether a quadratic equation has two different solutions, one (two coinciding) solution or no (real) solution at all we have to look at the discriminant. In this case:

D=4-4q\cdot{q}

The equation has two coinciding solutions if:

4-4q^2=0

or:

q^2-1=0

We can calculate the values of q by solving the equation. This can be done in two different ways.
We can apply the special product:

a^2-b^2=(a+b)(a-b)

In this case this means:

q^2-1=(q+1)(q-1)=0

and thus the solutions are:

q=1 or q=-1

We can also get the same result by solving:

q^2=1

but quite often the negative solution will be forgotten.

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