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Solution assignment 03 Equations with fractions

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Assignment 3

Solve:

\displaystyle\frac{x-3}{x+3}=\displaystyle\frac{x-4}{x+4}

Solution

Cross-multiplication yields:

(x-3)(x+4)=(x-4)(x+3)

x^2+x-12=x^2-x-12

x=0

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